Algebra 1

How to simplify square roots and radicals

To simplify a square root, find the largest perfect square that divides the number under the root, split it off, and take its square root. For example, 72=36⋅2=62\sqrt{72} = \sqrt{36 \cdot 2} = 6\sqrt{2}. You can only add or subtract radicals with the same number under the root, like 32+52=823\sqrt{2} + 5\sqrt{2} = 8\sqrt{2}. A simplified answer has no square root left in a denominator.

Updated

The key idea

A square root of a product splits into a product of square roots. If one of the pieces is a perfect square, its root is a whole number and can leave the radical sign:

ab=a⋅bso72=36⋅2=62\sqrt{ab} = \sqrt{a}\cdot\sqrt{b} \qquad\text{so}\qquad \sqrt{72} = \sqrt{36}\cdot\sqrt{2} = 6\sqrt{2}

It helps to know the perfect squares by sight: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144. A radical is fully simplified when no perfect square (other than 1) divides the number under the root, and there is no root in a denominator.

Worked examples

Example 1: pull out the largest perfect square

Problem Simplify 72\sqrt{72}.

  1. The largest perfect square that divides 72 is 36.
    72=36⋅2\sqrt{72} = \sqrt{36 \cdot 2}
  2. Split the root and take 36=6\sqrt{36} = 6.
    36⋅2=36⋅2=62\sqrt{36 \cdot 2} = \sqrt{36}\cdot\sqrt{2} = 6\sqrt{2}

Answer 626\sqrt{2}

Example 2: a radical with a variable

Problem Simplify 50x3\sqrt{50x^3}, where x≥0x \ge 0.

  1. Split into the perfect-square part and the rest. 50=25⋅250 = 25 \cdot 2 and x3=x2⋅xx^3 = x^2 \cdot x.
    50x3=25x2⋅2x\sqrt{50x^3} = \sqrt{25x^2 \cdot 2x}
  2. 25x2=5x\sqrt{25x^2} = 5x, because (5x)2=25x2(5x)^2 = 25x^2. The 2x2x stays inside.
    25x2⋅2x=5x 2x\sqrt{25x^2 \cdot 2x} = 5x\,\sqrt{2x}

Answer 5x 2x5x\,\sqrt{2x}

Example 3: add and subtract radicals

Problem Simplify 312+27−753\sqrt{12} + \sqrt{27} - \sqrt{75}.

  1. These look unlike, so simplify each one first. 12=4⋅312 = 4 \cdot 3, 27=9⋅327 = 9 \cdot 3, 75=25⋅375 = 25 \cdot 3.
    312+27−75=3⋅23+33−533\sqrt{12} + \sqrt{27} - \sqrt{75} = 3 \cdot 2\sqrt{3} + 3\sqrt{3} - 5\sqrt{3}
  2. Now all three are multiples of 3\sqrt{3}. Combine them like 6y+3y−5y6y + 3y - 5y.
    63+33−53=436\sqrt{3} + 3\sqrt{3} - 5\sqrt{3} = 4\sqrt{3}

Answer 434\sqrt{3}

Example 4 (test-hard): rationalize, then combine

Problem Simplify 105+20\frac{10}{\sqrt{5}} + \sqrt{20}.

  1. Rationalize: multiply the top and the bottom by 5\sqrt{5}. That is multiplying by 1, so the value does not change, and 5⋅5=5\sqrt{5} \cdot \sqrt{5} = 5.
    105=105⋅55=1055=25\frac{10}{\sqrt{5}} = \frac{10}{\sqrt{5}} \cdot \frac{\sqrt{5}}{\sqrt{5}} = \frac{10\sqrt{5}}{5} = 2\sqrt{5}
  2. Simplify the second radical.
    20=4⋅5=25\sqrt{20} = \sqrt{4 \cdot 5} = 2\sqrt{5}
  3. Now they match, so add.
    25+25=452\sqrt{5} + 2\sqrt{5} = 4\sqrt{5}

Answer 454\sqrt{5}

Common mistakes

  • Splitting a root over a sum. 9+16=25=5\sqrt{9 + 16} = \sqrt{25} = 5, not 3+4=73 + 4 = 7. Splitting only works for multiplication.
  • Stopping too early. 72=218\sqrt{72} = 2\sqrt{18} is true but not finished, since 18 still contains 9. Fix: use the largest perfect square, or keep going.
  • Adding unlike radicals. 2+3\sqrt{2} + \sqrt{3} is not 5\sqrt{5}. Only radicals with the same number inside combine.
  • Losing the outside number. In 3123\sqrt{12}, the 2 that comes out multiplies the 3: 3⋅23=633 \cdot 2\sqrt{3} = 6\sqrt{3}.
  • Leaving a root in the denominator. Most teachers want 105\frac{10}{\sqrt{5}} written as 252\sqrt{5}.

Quick methods

Practice

5 practice questions

  1. Simplify 48\sqrt{48}.

    1. 434\sqrt{3}
    2. 343\sqrt{4}
    3. 626\sqrt{2}
    4. 16316\sqrt{3}
    Show answer

    Answer: 434\sqrt{3}

    48=16⋅348 = 16 \cdot 3, and 16=4\sqrt{16} = 4. The choice 16316\sqrt{3} forgets to take the square root of 16. 626\sqrt{2} is 72\sqrt{72}, and 343\sqrt{4} is just 6.

  2. Simplify 218+82\sqrt{18} + \sqrt{8}.

    1. 828\sqrt{2}
    2. 2262\sqrt{26}
    3. 3263\sqrt{26}
    4. 10210\sqrt{2}
    Show answer

    Answer: 828\sqrt{2}

    18=32\sqrt{18} = 3\sqrt{2}, so 218=622\sqrt{18} = 6\sqrt{2}. 8=22\sqrt{8} = 2\sqrt{2}. Together that is 828\sqrt{2}. The choices with 26 add the numbers under the roots, which is not allowed.

  3. Simplify (32)(46)(3\sqrt{2})(4\sqrt{6}).

    1. 24324\sqrt{3}
    2. 12312\sqrt{3}
    3. 7127\sqrt{12}
    4. 12812\sqrt{8}
    Show answer

    Answer: 24324\sqrt{3}

    Multiply outside by outside and inside by inside: 121212\sqrt{12}. Then 12=23\sqrt{12} = 2\sqrt{3}, so the result is 24324\sqrt{3}. The choice 12312\sqrt{3} forgets the 2 that came out of 12\sqrt{12}.

  4. Rationalize the denominator: 82\frac{8}{\sqrt{2}}.

    1. 424\sqrt{2}
    2. 828\sqrt{2}
    3. 44
    4. 222\sqrt{2}
    Show answer

    Answer: 424\sqrt{2}

    Multiply top and bottom by 2\sqrt{2}: 822=42\frac{8\sqrt{2}}{2} = 4\sqrt{2}. The choice 828\sqrt{2} multiplies the top but forgets that the bottom became 2.

  5. What is 81+144\sqrt{81 + 144}?

    1. 1515
    2. 2121
    3. 12.512.5
    4. 225225
    Show answer

    Answer: 1515

    Add first: 81+144=22581 + 144 = 225, and 225=15\sqrt{225} = 15. The trap 21 is 9+129 + 12, which splits the root over a sum. 225 forgets to take the root.

Frequently asked questions

What makes a square root fully simplified?

Three things. No perfect square other than 1 divides the number under the root. There is no fraction under the root. And there is no root in the denominator. So 626\sqrt{2} is simplified, but 2182\sqrt{18} and 105\frac{10}{\sqrt{5}} are not.

Can you add square roots?

Only like ones, with the same number under the root. Treat 3\sqrt{3} like a variable: 63+33=936\sqrt{3} + 3\sqrt{3} = 9\sqrt{3}. If they look different, simplify each first, because 12\sqrt{12} and 27\sqrt{27} both turn into multiples of 3\sqrt{3}.

Why do we rationalize the denominator?

It is a convention that makes answers easy to compare and combine. 105\frac{10}{\sqrt{5}} and 252\sqrt{5} are the same number, but the second form can be added to other multiples of 5\sqrt{5} right away, as in Example 4.

How do I simplify a square root with variables?

Split each variable power into an even part and what is left. Even powers come out at half the exponent: x2=x\sqrt{x^2} = x and x6=x3\sqrt{x^6} = x^3 when x is not negative. So x5=x4⋅x=x2x\sqrt{x^5} = \sqrt{x^4 \cdot x} = x^2\sqrt{x}.

Try asking Ducky

  • “What's the biggest perfect square inside 180?”
  • “Why can't I just add the numbers under the square roots?”
  • “Walk me through rationalizing this denominator.”

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